Check for leap year in Shell Script
By: Vivek G
This shell script accepts a year and checks if the entered year is leap year or not.year=0
echo -n "Enter the year, I will tell you whether its Leap year or Not? "
read year
ans=$(($year % 4)) # or try ans=`expr $year % 2`
if [ $ans -eq 0 ]; then
echo "$year is Leap Year"
else
echo "$year is NOT Leap Year"
fi
Archived Comments
1. this is WRONG!
your IF should be:
if [[ $(($year % 4)) == 0 &&
View Tutorial By: notnooblikeyou at 2013-01-29 15:11:30
2. simple and effective
View Tutorial By: rams at 2012-09-13 04:10:11
Comment on this tutorial
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