Print contents of a file using Shell Script
By: Vivek G in Linux Tutorials on 2011-01-29
This shell script prints contents of file from given line number to next given number of lines. For e.g. If we called this script as printfile and run as $ printfile 5 5 myfile , Here print contents of 'myfile' file from line number 5 to next 5 line of that file.
if [ $# -eq 0 ]
then
echo "$0:Error command arguments missing!"
echo "Usage: $0 start_line uptoline filename"
echo "Where start_line is line number from which you would like to print file"
echo "uptoline is line number upto which would like to print"
echo "For eg. $0 5 5 myfile"
echo "Here from myfile total 5 lines printed starting from line no. 5 to"
echo "line no 10."
exit 1
fi
#
# Look for sufficent arg's
#
if [ $# -eq 3 ]; then
if [ -e $3 ]; then
tail +$1 $3 | head -n$2
else
echo "$0: Error opening file $3"
exit 2
fi
else
echo "Missing arguments!"
fi
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