By: Vivek G in Linux Tutorials on 2011-01-29This shell script prints contents of file from given line number to next given number of lines. For e.g. If we called this script as printfile and run as $ printfile 5 5 myfile , Here print contents of 'myfile' file from line number 5 to next 5 line of that file.
if [ $# -eq 0 ] then echo "$0:Error command arguments missing!" echo "Usage: $0 start_line uptoline filename" echo "Where start_line is line number from which you would like to print file" echo "uptoline is line number upto which would like to print" echo "For eg. $0 5 5 myfile" echo "Here from myfile total 5 lines printed starting from line no. 5 to" echo "line no 10." exit 1 fi # # Look for sufficent arg's # if [ $# -eq 3 ]; then if [ -e $3 ]; then tail +$1 $3 | head -n$2 else echo "$0: Error opening file $3" exit 2 fi else echo "Missing arguments!" fi
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