Java program to check if user input is an even number
By: Paawan Chaudhary in Java Tutorials on 2012-09-19
This is a java program to accept a number from the user and throw an exception if the number is not an even number.
import java.lang.*;
import java.io.*;
class myException extends Exception
{
myException(String msg)
{
super(msg);
}
}
class q12Exception
{
public static void main(String args[])
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n;
try
{
System.out.println ("Enter a no.");
n=Integer.parseInt(br.readLine());
if(n%2==0)
{
System.out.println ("No. is even");
}
else
{
throw new myException("No. is not even");
}
}
catch(myException me)
{
System.out.println (me);
}
catch(IOException ie)
{
System.out.println (ie);
}
}
} Add Comment
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