Bubble Sort in Java
By: SPlutard in Java Tutorials on 2011-01-29
The Bubble Sort method works like this: In a series of n-1 iterations, the successive elements, list[index] and list[index + 1] of list are compared. If list[index] is greater than list[index + 1], then the elements of list[index] and list[index + 1] are swapped.
This process is repeated through the list until no swaps are necessary. On average, for a list with length 'n', the Bubble Sort method takes:
* key comparisons: (n*(n-1))/2 * item assignments: (n*(n-1))/4
public class TestBubbleSort { public static void main(String[] args) { int unsortedArray[] = {10, 97, 6, 23, 0, -45, 697, -1000, 1, 0}; //Random set of numbers for example. int i; bubbleSort(unsortedArray, unsortedArray.length); //Pass the array to be sorted and its length. System.out.println("After sorting, the list elements are: "); //Just to show you it worked. :) for(i=0; i<unsortedArray.length; i++) { System.out.print(unsortedArray[i] + " "); } } private static void bubbleSort(int[] unsortedArray, int length) { int temp, counter, index; for(counter=0; counter<length-1; counter++) { //Loop once for each element in the array. for(index=0; index<length-1-counter; index++) { //Once for each element, minus the counter. if(unsortedArray[index] > unsortedArray[index+1]) { //Test if need a swap or not. temp = unsortedArray[index]; //These three lines just swap the two elements: unsortedArray[index] = unsortedArray[index+1]; unsortedArray[index+1] = temp; } } } } }
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