Creating JSON objects using Java in AJAX
By: Emiley J.
To build the JSON object programmatically in Java, you can keep it simple by just constructing a StringBuffer by appending the values or you can use the JSONObject provided by json.org to construct the JSON object easily.
The simpler way to do using StringBuffer is as follows:
public String createJSON(int value){
StringBuffer rjson = new StringBuffer("\r\n{\"conversion\":{");
rjson.append("\r\n\"decimal\": \"" +
Integer.toString(value)+"\",");
rjson.append("\r\n\"hexadecimal\": \"" +
Integer.toString(value,16)+"\",");
rjson.append("\r\n\"Octal\": \"" +
Integer.toString(value,8)+"\",");
rjson.append("\r\n\"Binary\": \"" +
Integer.toString(value,2)+"\",");
rjson.append("\r\n}}");
return rjson.toString();
}
The alternate way to create the JSON object is to use the JSON library.
Remember to download and put the latest json_simple-1.0.2.jar in your CLASSPATH
import org.json.simple.JSONObject;
JSONObject obj=new JSONObject();
obj.put("name","foo");
obj.put("num",new Integer(100));
obj.put("balance",new Double(1000.21));
obj.put("is_vip",new Boolean(true));
obj.put("nickname",null);
System.out.print(obj);
Archived Comments
1. how to run a ajax code in eclipse.plzzz publish with screenshots..as soon as possible
View Tutorial By: purnima at 2015-11-06 06:09:42
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