Creating JSON objects using Java in AJAX

By: Emiley J. Printer Friendly Format

To build the JSON object programmatically in Java, you can keep it simple by just constructing a StringBuffer by appending the values or you can use the JSONObject provided by json.org to construct the JSON object easily.

The simpler way to do using StringBuffer is as follows:

public String createJSON(int value){

StringBuffer rjson = new StringBuffer("\r\n{\"conversion\":{");

rjson.append("\r\n\"decimal\": \"" +
Integer.toString(value)+"\",");

rjson.append("\r\n\"hexadecimal\": \"" +
Integer.toString(value,16)+"\",");

rjson.append("\r\n\"Octal\": \"" +
Integer.toString(value,8)+"\",");

rjson.append("\r\n\"Binary\": \"" +
Integer.toString(value,2)+"\",");

rjson.append("\r\n}}");

return rjson.toString();

}

The alternate way to create the JSON object is to use the JSON library.

Remember to download and put the latest json_simple-1.0.2.jar in your CLASSPATH

import org.json.simple.JSONObject;

 
JSONObject obj=new JSONObject();
  

 obj.put("name","foo");
  

 obj.put("num",new Integer(100));
  

 obj.put("balance",new Double(1000.21));
  

 obj.put("is_vip",new Boolean(true));
  

 obj.put("nickname",null);
  

 System.out.print(obj);